Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 21: 21

Answer

120 m

Work Step by Step

∠ BAC = 180 - 51 - 77 = 52$^{\circ}$ Using cosine rule: $cos(52^{\circ})=\frac{62^{2}+x^{2}-95^{2}}{2(62)(x)}$ 0.61566 = $\frac{x^{2}-5181}{124x}$ 76$x$ = $x^{2}$ - 5181 $x^{2}$ - 76$x$ - 5181 = 0 Using quadratic equation: $x = \frac{-(-76)±\sqrt ((-76)^{2}=4(1)(-5181))}{2(1)}$ $x\approx 120$ m since $x\gt0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.