Answer
0.83 J
Work Step by Step
Force and displacement are in the same direction. The angle between them is 0.
$W=Fd\cos\theta=Fd\cos0^{\circ}=Fd$
Now, displacement $d=ut+\frac{1}{2}at^{2}$.
But initial velocity u=0 and acceleration $a=\frac{F}{m}$.
Therefore $d=\frac{1}{2}\times\frac{F}{m}\times t^{2}$
$\implies W=Fd=F\times\frac{1}{2}\times\frac{F}{m}\times t^{2}$
$=\frac{F^{2}\times t^{2}}{2m}$
Given: $F=5.0\,N$, $t=1\,s$ and $m=15\,kg$
Result: $W=\frac{(5.0\,N)^{2}\times(1\,s)^{2}}{2\times15\,kg}=0.83\,J$
