Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Questions - Page 116: 12

Answer

We can rank the choices according to the magnitude of the normal force acting on the block from the plane: $d \gt c \gt a \gt b$

Work Step by Step

The magnitude of the normal force acting on the block from the plane is equal to the sum of the component of the block's weight directed into the plane and the component of the force directed into/out of the plane. We can find an expression for the magnitude of the normal force $F_N$ for each applied force: $a$ $F_N = mg~cos~30^{\circ}- F~sin~30 = 0.866~mg-0.5~F$ $b$ $F_N = mg~cos~30^{\circ}- F~cos~30 = 0.866~mg-0.866~F$ $c$ $F_N = mg~cos~30^{\circ}+ F~sin~30 = 0.866~mg+0.5~F$ $d$ $F_N = mg~cos~30^{\circ}+ F~cos~30 = 0.866~mg+0.866~F$ We can rank the choices according to the magnitude of the normal force acting on the block from the plane: $d \gt c \gt a \gt b$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.