Answer
$p\longrightarrow \hspace{2mm}e^+ \hspace{2mm}+ \hspace{2mm}\nu_e$
This is the decay scheme. Let it be called equation 1. This does not violate conservation law of charge.
Work Step by Step
Let $1.6\times 10^{-19}$ C charge be called one unit charge.
The charge of proton ($p$) in this new system is $+1$.
The charge of positron ($e^+$) is $+1$.
Neutrino ($\nu_e$) is chargeless.
The total charge of the Left-hand side of equation 1 is $+1.$
The total charge of the Right-hand side of equation 1 is $+1+0=+1$.
Thus there is charge conservation.
