Answer
Yes, there will be a time $t$ when $R_A = R_B$
Work Step by Step
We can write an expression for the decay rate:
$R = R_0~e^{-\lambda t} = \frac{R_0}{e^{\lambda t}}$
Initially, $R_A \gt R_B$
However, since $\lambda_A \gt \lambda_B$, as time increases, $R_A$ decreases more steeply than $R_B$.
Therefore, there will be a time $t$ when $R_A = R_B$
