Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 41 - Conduction of Electricity in Solids - Problems - Page 1275: 53

Answer

$P = 3.49 \times 10^3 atm$

Work Step by Step

We use the equation of ideal gas $P = {NkT } $ Where $N=8.43\times10^{28} m ^{-3}$ $k = 1.38 \times 10^{-23} J/K$ $T= 300K$ So $P = (8.43\times10^{28} m ^{-3})(1.38 \times 10^{-23} J/K)(300K) $ $P = 3.49 \times 10^8 Pa$ Change unit to atm assuming $1 Pa = 1 \times 10^{-5} atm$, so $P = 3.49 \times 10^3 atm$
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