Answer
$\theta =60^{\circ}$
Work Step by Step
We can express the car's speed in units of $m/s$:
$v = (50~km/h)(\frac{1~h}{3600~s})(\frac{1000~m}{1~km})$
$v = 13.89~m/s$
Relative to the driver, the snow is moving with a vertical velocity of $8.0~m/s$ and a horizontal velocity of $13.89~m/s$
We can find the angle $\theta$ from the vertical:
$tan~\theta = \frac{13.89~m/s}{8.0~m/s}$
$\theta = tan^{-1}~(\frac{13.89~m/s}{8.0~m/s})$
$\theta =60^{\circ}$
