Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 86: 36a

Answer

$y= 1.105m$

Work Step by Step

$v_{o} = 23.6m/s$ Find t using this equation: $x=({v_{o}}$ $cos\theta)t$ $t=\frac{({v_{o}} \times cos\theta)}{x}$ $t=\frac{({23.6m/s}\times cos0^{\circ})}{12}$ $t=0.508s$ Formula for finding height: $y=y_{o} + (v_{o}$ $sin\theta)t-\frac{1}{2}gt^{2}$ $y=2.37 + (23.6$ $sin$ $0^{\circ})t-\frac{1}{2}9.8 \times 0.508^{2}$ $y= 1.105m$
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