Answer
$3.61~kW$
Work Step by Step
We can find the rate at which solar energy arrives at the panel:
$Power = I~A = (1.39~kW/m^2)(2.60~m^2) = 3.61~kW$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 38 - Photons and Matter Waves - Problems - Page 1181: 10a
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