Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1150: 69e

Answer

$L'=0.379m$

Work Step by Step

Length contraction states that the length of an object moving with the value gamma will have a length of $$L'=\frac{L_c}{\gamma}$$ The formula for gamma is $$\gamma=\frac{1}{\sqrt{1-\beta ^2}}$$ Using the value of $v=-0.9980c$ and $\beta=-0.9980$, gamma is equal to $$\gamma=\frac{1}{\sqrt{1-(-.9980)^2}}=15.82$$ Substituting known values of $L_c=30.5m$ and $\gamma=15.82$ yields an apparent length of $$L'=\frac{6.00m}{15.82}=0.379m$$
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