Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1115: 98

Answer

$L=160m$

Work Step by Step

We know that: $\theta=\frac{y}{L}=1.22(\frac{\lambda}{d})$ This can be rearranged as: $L=\frac {yd}{(1.22\lambda)}$ We plug in the known values to obtain: $L=\frac{0.02\times 0.005}{(1.22\times 500\times 10^{-9})}=160m$
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