Answer
The path length difference is $~~300~nm$
Work Step by Step
We can find the extra distance traveled by the upper ray:
$d = 150~nm+150~nm = 300~nm$
The path length difference is $~~300~nm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 35 - Interference - Questions - Page 1073: 8a
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