Answer
$d=33\mu m$
Work Step by Step
We know that:
$dsin(\theta)=\lambda$
This can be written as:
$d=\frac{\lambda}{sin(\theta)}$
We plug in the known values to obtain:
$d=\frac{589nm}{sin(0.018)}=33\mu m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 35 - Interference - Problems - Page 1080: 101
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