Answer
$\vec{D}$ and $\vec{E}$ have negative dot product with $\vec{A}$.
Work Step by Step
Recall the dot product formula:
$\vec{a} \cdot \vec{b} = |a| |b| cos\phi$
Since both $\vec{D}$ and $\vec{E}$ have the same length and cosine is negative in the II and III quadrants, $\vec{D}$ and $\vec{E}$ have negative dot product with $\vec{A}$.
