Answer
$79.0^{\mathrm{o}}$
Work Step by Step
$(1.28m)\hat{\mathrm{i}}+(6.60m)\hat{\mathrm{j}}$ points to quadrant I.
Thus, using (3-6),
$\displaystyle \theta=\tan^{-1}(\frac{6.60}{1.28})=79.0^{\mathrm{o}}$
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