Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 28 - Magnetic Fields - Problems - Page 829: 4b

Answer

$a=9.5\times 10^8\frac{m}{s^2}$

Work Step by Step

We will use the following equation to solve this question: $F_B=ma$ First, we need to rearrange this equation to make $a$ the subject of the equation: $a=\frac{F_B}{m}$ We plug in the known values to obtain: $a=\frac{6.24\times 10^{-18}}{6.6\times 10^{-27}}$ $a=9.5\times 10^8\frac{m}{s^2}$
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