Answer
The force $F_2$ tends to rotate the disk counterclockwise.
Work Step by Step
We can write a general expression for the torque:
$\tau = r \times F$
$r$ is the displacement vector from the axis of rotation to the point where the force is applied
$F$ is the force vector
By the right hand rule, $r \times F_2$ is out of the page.
By the right hand rule, the force $F_2$ tends to rotate the disk counterclockwise.
