Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 287: 2c

Answer

$\omega=1.45\times10^{-4} \frac{rad}{s}$

Work Step by Step

The hour hand of a clock completes a round trip in 12 hours. Since one hour is 3600 seconds, 12 hours equal: $3600\times 12=43200$sec Thus, the angular speed of hour hand is given as $\omega=\frac{2\pi}{43200}=\frac{2(3.1416)}{43200}$ $\omega=1.45\times10^{-4} \frac{rad}{s}$
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