Answer
The distance from the Earth to the Sun is 4.9 x 10$^{-6}pc$
Work Step by Step
$(\frac{1arcmin}{60arcsec})(\frac{1^{\circ}}{60arcmin})(\frac{2πrad}{360^{\circ}})=4.85\times10^{-6}rad$
$1pc=\frac{1AU}{4.85\times10^{-6}}=2.06\times10^{5}AU$
$1AU=1pc/(2.06\times10^{5})=4.9\times10^{-6}pc$
