Answer
$49 \ m/s$
Work Step by Step
We find:
$v_p = \frac{(m_p+m_c)v_c}{m_p} = (.16+6.4)(1.2)/.16 \approx 49 \ m/s$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 9 - Section 9.5 - Totally Inelastic Collisions - Example - Page 155: 9.7
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