Answer
$v=2.69\times10^5\ m/s$
$\theta=18^{\circ}$
Work Step by Step
We first find the speed. Since momentum is conserved, it follows:
$238(5\times10^5)=4(1.4\times10^7)+234v$
$v=2.69\times10^5\ m/s$
We now find the angle:
$\theta = tan^{-1}(\frac{4(1.4\times10^7)\times sin22}{2.69\times10^5\times234})$
$\theta=18^{\circ}$
