Answer
Please see the work below.
Work Step by Step
We know that
$F=-\frac{dU}{dr}$
$F=-(\frac{GMm}{r})^{\prime}$
$F=-(GMm)(\frac{1}{r})^{\prime}$
$F=-(GMm)(-\frac{1}{r^2})$
$F=\frac{GMm}{r^2}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 8 - Exercises and Problems - Page 141: 38
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