Answer
a) 1510 MJ
b) $12^{\circ}$
Work Step by Step
We use the equation for work:
$W = F_x\Delta x + F_y\Delta y$
$W = (1.2)(380) + (2.3)(460) = 1510 \ MJ$
We use the Pythagorean theorem to find:
$ F = \sqrt{ 1.2^2 + 2.3^2} = 2.59 \ MN$
Thus:
$\theta = cos^{-1} (\frac{1510}{2.59 \times 597}) \approx 12^{\circ}$
