Answer
Please see the work below.
Work Step by Step
We know that
$P=\frac{mgh}{t}$
$\implies P=\frac{mgdsin(\theta)}{t}$
$P=mgsin(\theta)(\frac{d}{t})$
$P=mgsin(\theta)(v)$
This can be rearranged as:
$v=\frac{P}{mgsin(\theta)}$
We plug in the known values to obtain:
$v=\frac{35000}{(1750)(9.8)sin(4.5)}$
$v=26\frac{m}{s}$
