Answer
220 Newtons
Work Step by Step
We find the two components of the forces:
x: $- T_2cos\theta + T_1 cos\theta=0$
y: $T_1 sin\theta - mg + T_2sin\theta=0$
We see that the two y tensions are equal, so we obtain:
$2Tsin\theta - mg = 0 \\ T = \frac{mg}{2sin\theta}= \frac{17 \times 9.81}{2sin22^{\circ}}= 220\ N$
