Answer
Please see the work below.
Work Step by Step
We know that
$F_x=ma$
We plug in the known values to obtain:
$F_x=(1400)(0.57)=798N$
Now we can find the tension as
$T=\frac{F_x}{cos25}=\frac{798}{cos25}=880N$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 5 - Exercises and Problems - Page 86: 17
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