Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 4 - Section 4.4 - The Force of Gravity - Example - Page 57: 4.2

Answer

$3.34 \ kN$

Work Step by Step

We first find the mass on earth: $ m = \frac{8.82 \ kN}{9.81 \ m/s^2}= 899\ kg $ We use the gravitational constant for Mars to find: $w = (3.71 m/s^2)(899kg)=3.34 \ kN$
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