Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 4 - Exercises and Problems - Page 70: 73

Answer

Please see the work below.

Work Step by Step

We know that $F-T-m_1g=m_1a$ This simplifies to: $m_1=\frac{F-T}{a+g}=\frac{30-18}{9.8+3.2}=0.92Kg$ For the other mass $T-m_2g=m_2a$ This simplifies to: $m_2=\frac{T}{g+a}$ $m_2=\frac{18}{9.8+3.2}=1.4Kg$
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