Answer
Please see the work below.
Work Step by Step
We know that
$t=\sqrt{\frac{2h}{g}}$
We plug in the known values to obtain:
$t=\sqrt{\frac{2(1.20)}{9.8}}=0.4949s$
The acceleration of the earth is given as
$a=\frac{F}{M_e}$
$a=\frac{mg}{M_e}$
$a=\frac{65(9.8)}{5.97\times 10^{24}}=1.067\times 10^{-22}\frac{m}{s^2}$
The displacement of the earth is given as
$d=\frac{1}{2}at^2=\frac{1}{2}(1.067\times 10^{-22})(0.4949)^2=1.3\times 10^{-23}m$
