Answer
Please see the work below.
Work Step by Step
We know that
$y=\frac{1}{2}g_{moon}t^2$
This simplifies to:
$t=\sqrt{\frac{2y}{g_{moon}}}$
We plug in the known values to obtain:
$t=\sqrt{\frac{2(12)}{1.62}}$
$t=3.8s$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 2 - Exercises and Problems - Page 30: 73
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