Answer
Please see the work below.
Work Step by Step
We know that
$\Delta d=142-23=119m$
Now $a=\frac{v^2-v_{\circ}^2}{2\Delta d}$
$a=\frac{(0.75)^2-(32)^2}{2.119}=4.3\frac{m}{s^2}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 2 - Exercises and Problems - Page 29: 51
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