Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 2 - Exercises and Problems - Page 28: 22

Answer

125 m/$s^{2}$

Work Step by Step

We use the equation for average acceleration to obtain: a̅= $\frac{\Delta v}{\Delta t}$ = $\frac{(450-0) km/s}{1 hr}$ = $\frac{450000 m/s}{3600s}$ = 125 m/$s^{2}$
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