Answer
$36.176\frac{J}{K}$
Work Step by Step
We know that
$\Delta S=\int_{T_1}^{T_2}\frac{C_p dT}{T}$
$\Delta S=n\int_{T_1}^{T_2}(\frac{a+bT+cT^2}{T})dT$
$=n(a\ln(\frac{T_2}{T_1})+b(T_2-T_1)+\frac{c(T_2^2-T_1^2)}{2})$
$=2\times 18.088\frac{J}{K}$
$=36.176\frac{J}{K}$
