Answer
99.95%
Work Step by Step
As we know that
$e_{max}=(1-\frac{T_c}{T_h})\times 100\%$
We plug in the known values to obtain:
$e_{max}=(1-\frac{2.7}{5800})\times 100\%=99.95\%$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 19 - Exercises and Problems - Page 349: 14
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