Answer
2.2R
Work Step by Step
We first find the internal energies of each of the gases:
$E_{intO_{2}}= \frac{5}{2}nRT=5RT$
$E_{int_{Ar}}= \frac{3}{2}nRT=1.5RT$
Adding the internal energies, we find:
$C_v=\frac{6.5RT}{nT}=\frac{6.5R}{3}=2.2R$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 18 - Section 18.3 - Specific Heats of an Ideal Gas - Example - Page 328: 18.5
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