Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 18 - Exercises and Problems - Page 332: 67

Answer

$p_1=135\ atm$

Work Step by Step

We use the ideal gas law and the equation $p_1V_1=p_2V_2$ to obtain: $Q = nRTln(\frac{p_1}{p_2}) \\ p_1 = p_2 e^{\frac{Q}{nRT}}\\p_1 = p_2 e^{\frac{mL_f}{nRT}} \\ p_1 = 1 \times e^{\frac{.01\times334,000}{.3\times8.314\times273}}$ $p_1=135\ atm$
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