Answer
216 K
Work Step by Step
We know that:
$\frac{T_2}{T_1} = { (\frac {V_1}{V_2})}^{ \gamma -1}$
We know that the volume is cut by a factor of 4 and that $\gamma$ is equal to 1.4. This gives:
$T_2= (\frac {4}{1})^{.4} \times 291 K$
We know:
$\Delta T = T_2-T_1=216 K$
