Answer
542 seconds
Work Step by Step
We first find the value of Q:
$Q = L_fm = (259)(2.5 \times10^5)=65GJ$
We use this to find the change in time:
$\Delta T=(65GJ)(.12 \ GJ/s)=542\ s$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 17 - Section 17.2 - Phase Changes - Example - Page 308: 17.3
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