Answer
$21^{\circ}C $
Work Step by Step
We use the equation for H to find:
$H = (120 \ W/^{\circ}C)(\Delta T)$
$\Delta T = \frac{H}{120 \ W/^{\circ}C} $
$\Delta T = \frac{2.5 \times 10^3 \ W}{120 \ W/^{\circ}C} = 21^{\circ}C $
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 16 - Section 16.4 - Thermal-Energy Balance - Example - Page 295: 16.6
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