Answer
$5.8 \times 10^3 \ K$
Work Step by Step
We simplify equation 16.9 to find:
$ P = (\frac{P}{4 \pi R^2 \sigma})^{1/4}$
$ P = (\frac{3.9 \times 10^{26}}{4 \pi (7 \times 10^8)^2(5.7 \times 10^{-8})})^{1/4}= 5.8 \times 10^3 \ K$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 16 - Section 16.3 - Heat Transfer - Example - Page 294: 16.5
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