Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 262: 16

Answer

Please see the work below.

Work Step by Step

We know that $c=f\lambda$ This can be rearranged as $\lambda=\frac{c}{f}$ We plug in the known values to obtain: $\lambda=\frac{3\times 10^8}{89.5\times 10^6}=3.35m$
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