Answer
8
Work Step by Step
We first find the time:
$t = \frac{2m}{b}ln2= \frac{2\times 1200}{230}ln2= 7.23 s$
We now find the period:
$T = 2\pi \sqrt{\frac{m}{k}}= 2\pi \sqrt{\frac{1200}{58 \times10^3 }}= .904s$
Thus:
$=\frac{7.23s}{.904s}\approx \fbox{8}$
