Answer
$9.2\times10^{26}N\cdot m$
Work Step by Step
Using the trendline, we find that the torque is equal to $.0039\times10^{37}kgm^2/s/yr$. From this, we find that the torque is:
$=\frac{.0029\times10^{37}kgm^2/s/yr}{31536000}=9.2\times10^{26}N\cdot m$
