Answer
a) $14.2 \ Js$
b) $57 \ Nm$
Work Step by Step
a) We use the parallel axis theorem to obtain:
$I_t = .048 +mR^2 = .048+(.88)(.43)^2 = .21$
Recall that $\omega=\frac{v}{r}$, it follows:
$L=I\omega=I\frac{v}{r}=(.021)\frac{50}{.74}=14.2 \ Js$
b) We obtain:
$\tau = \frac{L}{t}=\frac{14.2}{.25}=57 \ Nm$
