Answer
32.85 meters
Work Step by Step
We use conservation of energy to find:
$mgh = \frac{1}{2}mv^2+I\omega^2 $
$mgh = \frac{1}{2}mv^2+I\frac{v^2}{r^2} $
$h = \frac{\frac{1}{2}mv^2+I\frac{v^2}{r^2}}{mg} $
$h = \frac{\frac{1}{2}(395)(23.6)^2+(2.1)\frac{23.6^2}{.26^2}}{(395)(9.81)}=\fbox{32.85 meters} $
