Answer
Please see the work below.
Work Step by Step
We can find the moment of inertia of the shaft as
$I=(\frac{1}{2})MR^2$
We plug in the known values to obtain:
$I=(\frac{1}{2})(6800)(0.85/2)^2$
$I=614 \ kg.m^2$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 10 - Exercises and Problems - Page 184: 26
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