Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 1 - Exercises and Problems - Page 12: 15

Answer

Please see the work below.

Work Step by Step

We can find the time period of cesium as $time \space period=\frac{1}{9,192,631,770}=1.09\times 10^{-10}s=0.109ns$
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