Answer
$$G \frac{(2m_{1})(2 m_{2})}{d^{2}} = 4 \times G \frac{m_{1} m_{2}}{d^{2}} $$
When the distance stays the same, and the mass of each of the planets is doubled, the gravitational force is four times what it was before.
Conceptual Physics (12th Edition)
by Hewitt, Paul G.
Published by
Addison-Wesley
ISBN 10:
0321909100
ISBN 13:
978-0-32190-910-7
Chapter 9 - Think and Solve - Page 178: 40
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