Answer
$$F = 4.1 \times 10^{-8} N $$
Work Step by Step
$$F= G \frac{m_{1} m_{2}}{d^{2}} = (6.67 \times 10^{-11} \frac {N \cdot m^{2}}{kg^{2}}) \frac{(3.0 kg )(6.4 \times 10^{23} kg)}{(5.6 \times 10^{10} m)^{2}}$$
Conceptual Physics (12th Edition)
by Hewitt, Paul G.
Published by
Addison-Wesley
ISBN 10:
0321909100
ISBN 13:
978-0-32190-910-7
Chapter 9 - Plug and Chug - Page 178: 37
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