Answer
Use Table 12.1 to find the density of gold: $19.3 \frac{g}{cm^{3}}$.
$$19.3 \frac{g}{cm^{3}} = \frac{1000 \; g}{V}$$
Solve for V = $51.8 cm^{3}$.
Conceptual Physics (12th Edition)
by Hewitt, Paul G.
Published by
Addison-Wesley
ISBN 10:
0321909100
ISBN 13:
978-0-32190-910-7
Chapter 13 - Think and Solve - Page 260-261: 43
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